Solution: Carbon has three naturally occurring isotopes: 12 C, 13 C, and 14 C. The heights of the peaks correspond to the natural abundances of the isotopes. b) Peak m/e ratio 35 Cl 35 lightest particle 37 Cl 37 35 Cl 35 Cl 70 (35 + 35) 35 Cl 37 Cl 72 (35 + 37) 37 Cl 37 Cl 74 (35 + 37) heaviest particle B2.2 Plan: Each peak in the mass spectrum of carbon represents a different isotope of carbon. So the mass of chlorine will have 5 peaks. There are three peaks for the three possible Cl 2 molecules: 35 Cl 35 Cl (both atoms are mass 35), 37 Cl 37 Cl (both atoms are mass 37), and 35 Cl 37 Cl (one atom is mass 35 and one is mass 37). Solution: a) There is one peak for the 35 Cl atom and another peak for the 37 Cl atom. The m/e ratio equals the mass divided by 1+. B2.1 Plan: There is one peak for each type of Cl atom and peaks for the Cl 2 molecule.
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